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^2-16A^2+96=0
We add all the numbers together, and all the variables
-16A^2=0
a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$A=\frac{-b}{2a}=\frac{0}{-32}=0$
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